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Calculator for conversion of numeric code of three digits capacitors in real value of the capacitor (nF, pF, and µF)

That code Java script allows you to make the conversion of the complicated values numeric printed papers in the capacitors in your real values in pF, nF and µF
As group some time to identify those codes then decided to create that script, that will aid you to discover her/it the value of your capacitor with easiness.
A certain pattern exists for capacitors up to 1000 pF the value it is given in pF
For capacitors up to 1µF the value is given in nF
And of 1µF in before the values are in µF
Then for that definition lack, we needed to know all those codes, to facilitate we can use that program

Example of use of the program of conversion of capacitors codes

Value in the Body of the capacitor 102J, what will be that:
The numbers 1 and 0 are always the first ones and second digits and the third é the amount of zeros, value in pF, what generates another problem how to convert values in pF for nF or µF, simple it is only to use the program below.
In our case 10 + 00--> 1000 pF and J is the tolerance J = 5%
Choose the values of 1st 2nd and 3rd digits + the letter of the tolerance if there is and later it is only to click in calculating, ready you have the value of the informed capacitor in pF nF and µF, it is easy to use.


Enter with the numeric value of the capacitor ex:102J

1st Digit	2nd digit	3rd Digit	Tolerance
		cap	+ / - %
	µf	nF	pF

Attention that program is just for codes of three numbers:
Example: value enrolled in the body of the capacitor 222 that according to the program that code is above same to 2200pF, but it exists other possible registrations in the body of a capacitor of 2200pF:

2n2 - that wants to say 2,2 nF.
2K2 - that wants to say 2200 pF.
.0022 - that saying 0.0022 µF.
0.0022 - that wants 0.0022 µF to say.
222 - that wants to say 2200 pF.

Moral of the history in electronics it exists several ways to say the same thing, in the in case you value enrolled in the body of the capacitor.